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Simplifying (8 + -1x2)(x + -1x3) = 0 Multiply (8 + -1x2) * (x + -1x3) (8(x + -1x3) + -1x2 * (x + -1x3)) = 0 ((x * 8 + -1x3 * 8) + -1x2 * (x + -1x3)) = 0 ((8x + -8x3) + -1x2 * (x + -1x3)) = 0 (8x + -8x3 + (x * -1x2 + -1x3 * -1x2)) = 0 (8x + -8x3 + (-1x3 + 1x5)) = 0 Combine like terms: -8x3 + -1x3 = -9x3 (8x + -9x3 + 1x5) = 0 Solving 8x + -9x3 + 1x5 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(8 + -9x2 + x4) = 0 Factor a trinomial. x((1 + -1x2)(8 + -1x2)) = 0 Factor a difference between two squares. x(((1 + x)(1 + -1x))(8 + -1x2)) = 0Subproblem 1
Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0Subproblem 2
Set the factor '(8 + -1x2)' equal to zero and attempt to solve: Simplifying 8 + -1x2 = 0 Solving 8 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x2 = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x2 = 0 + -8 -1x2 = 0 + -8 Combine like terms: 0 + -8 = -8 -1x2 = -8 Divide each side by '-1'. x2 = 8 Simplifying x2 = 8 Take the square root of each side: x = {-2.828427125, 2.828427125}Subproblem 3
Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1Subproblem 4
Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1Solution
x = {0, -2.828427125, 2.828427125, -1, 1}
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